Factor 2g^3 - g^2 - 8g + 4
A. (g - 1)(2g^2 - 4)
B. (2g - 1)(g^2 - 4)
C. (2g^2 - 1)(g - 4)
D. (2g + 1)(g^2 - 4)
To factor 2g^3 - g^2 - 8g + 4, we can first group terms:
2g^3 - g^2 - 8g + 4
= 2g^2(g - 1) - 4(2g - 1)
= (2g^2 - 4)(g - 1)
Therefore, the correct factorization is A. (g - 1)(2g^2 - 4)