A running track in the shape of an oval is shown. The ends of the track form semicircles.
A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 56 m and length of one straight edge 130 m.
What is the perimeter of the inside of the track?
(π = 3.14)
260.00m
347.92m
372.00m
435.84m
The perimeter of the inside of the track can be calculated by adding the lengths of all four sides.
The two straight edges at the top and bottom are both 130m each, so combined they have a length of 260m.
The two curved edges, which are semicircles, each have a radius of 28m (half of the width of the track). The formula for the circumference of a circle is C = 2πr, so the circumference of each semicircle is 2 * π * 28 = 56π. Since there are two semicircles, the total length of the two curved edges is 112π.
Therefore, the perimeter of the inside of the track is 260m + 112π. Plugging in the value of π = 3.14, we get:
260 + 112 * 3.14 = 260 + 351.68 ≈ 435.84m
So, the correct answer is 435.84m.