A running track in the shape of an oval is shown. The ends of the track form semicircles.
A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 56 m and length of one straight edge 130 m.
What is the perimeter of the inside of the track?
(π = 3.14)
The perimeter of the inside of the track can be calculated by finding the perimeter of the oval shape formed by the two semicircles and the two straight edges.
Perimeter of a semicircle = πr + 2r (where r is the radius)
Perimeter of a straight edge = length
Given that the width of the track is 56 m, the radius (r) of the semicircles would be half of the width, so r = 56/2 = 28 m.
Perimeter of the left semicircle = π(28) + 2(28) = 88.48 + 56 = 144.48 m
Perimeter of the right semicircle = π(28) + 2(28) = 88.48 + 56 = 144.48 m
Perimeter of the top straight edge = Perimeter of the bottom straight edge = 130 m
Therefore, the total perimeter of the inside of the track is:
Perimeter = 144.48 m + 130 m + 130 m = 404.96 meters
So, the perimeter of the inside of the track is 404.96 meters.