Calculate the volume of 68.7 g of CO gas at STP. Be sure your answer has the correct number of significant figures.
Note: Reference the Fundamental Constants table for additional information.
To calculate the volume of 68.7 g of CO gas at STP, we first need to determine the molar mass of CO (carbon monoxide).
The molar mass of CO = 12.01 g/mol (for C) + 16.00 g/mol (for O) = 28.01 g/mol
Next, we need to convert the given mass of CO gas (68.7 g) to moles using the molar mass:
68.7 g CO x (1 mol CO / 28.01 g CO) = 2.45 mol CO
Now that we know the number of moles of CO gas, we can use the ideal gas law formula to calculate the volume:
V = nRT/P
Where:
V = volume
n = number of moles
R = ideal gas constant = 0.0821 L.atm/mol.K
T = temperature = 273 K (STP)
P = pressure = 1 atm (STP)
Plugging in the values:
V = 2.45 mol x 0.0821 L.atm/mol.K x 273 K / 1 atm
V = 50.7 L
Therefore, the volume of 68.7 g of CO gas at STP is 50.7 L. Since the given mass has four significant figures, the answer should also have four significant figures.