calculate the maximum volume of ammonia gas at stp which could be obtained by boiling 8dm(cube)of 0.651g solution of ammonia (molar volume of gas at stp=22.4dm).
I assume you have a solution containing 0.651 g NH3 in that 8 dm^3. So you can get 0.651 g NH3 if you get all of it and that will occupy, @ STP, 22.4 L/mol. How many moes do you have? That's 0.651/17 = about 0.0382 moles NH3 so the volume will be 0.382 x 22.4 dm^3/mol. By the way, the molar volume is 22.4 moles/dm^3
To calculate the maximum volume of ammonia gas at STP that could be obtained by boiling the solution, we need to find the number of moles of ammonia in the solution and then use the molar volume of gas at STP to calculate the volume.
Step 1: Calculate the number of moles of ammonia in the solution.
Given:
- Volume of the solution (V_solution) = 8 dm³
- Mass of the solution (m_solution) = 0.651 g
- Molar mass of ammonia (Molar mass_NH3) = 17.03 g/mol
We can use the formula:
Number of moles (n) = mass (m) / molar mass (M)
n = m_solution / Molar mass_NH3
n = 0.651 g / 17.03 g/mol
n ≈ 0.0382 mol
Step 2: Calculate the maximum volume of ammonia gas using the molar volume.
Given:
- Molar volume of gas at STP (V_molar) = 22.4 dm³/mol
The maximum volume of gas (V_gas) can be calculated as:
V_gas = n * V_molar
V_gas = 0.0382 mol * 22.4 dm³/mol
V_gas ≈ 0.856 dm³
Therefore, the maximum volume of ammonia gas at STP that could be obtained by boiling 8 dm³ of the solution is approximately 0.856 dm³.
To calculate the maximum volume of ammonia gas that can be obtained, we need to use the following steps:
1. Determine the number of moles of ammonia in the solution.
2. Use Avogadro's law to convert the number of moles to the volume of gas at STP.
Let's go through each step in detail:
Step 1: Determine the number of moles of ammonia in the solution.
To do this, we need to convert the given mass of ammonia solution (0.651g) to moles. We can use the formula:
moles = mass / molar mass
The molar mass of ammonia (NH3) is:
Nitrogen (N): 14.01 g/mol
Hydrogen (H): 1.01 g/mol (x 3 H atoms)
Molar mass of NH3 = (14.01 g/mol) + (1.01 g/mol x 3) = 17.03 g/mol
Using this molar mass, we can calculate the number of moles of ammonia:
moles = 0.651g / 17.03 g/mol
Step 2: Use Avogadro's law to convert the number of moles to the volume of gas at STP.
Avogadro's law states that one mole of any gas at STP occupies a volume of 22.4 liters (dm³). So, we can use this relationship to calculate the maximum volume of ammonia gas:
volume = moles x molar volume
volume = moles x 22.4 dm³/mol
Now, substitute the value of moles calculated in Step 1 into the equation:
volume = (0.651g / 17.03 g/mol) x 22.4 dm³/mol
Simplify the equation to find the maximum volume of ammonia gas at STP.