In the figure below AB ≅ED and CB ≅CD .
Which conclusion is ALWAYS true?
A. BC =1/2 AC
¯B. DB ∥ AE
←→ ←→
C. ∠E ≅∠C
D. AC = AB + ED
The correct answer is C. ∠E ≅∠C
This is always true because if AB ≅ ED and CB ≅ CD, then the corresponding angles opposite those sides will always be congruent. So ∠E will always be congruent to ∠C.