What is the slope and the y -intercept of the equation 9+27/2x=−3/2y . Write the y -intercept as an ordered pair.(1 point)%0D%0AThe slope is . The y-intercept is
The equation 9 + 27/2x = -3/2y can be written in slope-intercept form (y = mx + b) by isolating y:
9 + 27/2x = -3/2y
27/2x = -3/2y - 9
27/2x = -3/2(y + 6)
y = -9/3 - 27/2x
y = -27/2x - 9
Therefore, the slope of the equation is -27/2 and the y-intercept can be found by setting x = 0:
y = -27/2(0) - 9
y = -9
So, the y-intercept in ordered pair form is (0, -9).
that was wrong
Apologies for the mistake. Let's try solving the equation again:
Given equation: 9 + 27/2x = -3/2y
To write it in the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept, we need to solve for y:
9 + 27/2x = -3/2y
27/2x = -3/2y - 9
27/2x = -3/2y - 18
27/2x = -3/2(y + 6)
y = -2x - 12
So, the slope is -2 and the y-intercept is -12.
The y-intercept as an ordered pair is (0, -12).
also wrong
Let's reevaluate the equation to find the correct slope and y-intercept:
Given equation: 9 + 27/2x = -3/2y
First, rewrite the equation in slope-intercept form (y = mx + b) by isolating y:
9 + 27/2x = -3/2y
27/2x = -3/2y - 9
27/2x = -3/2y - 18
27x = -27y - 36
y = -27/27x - 36/27
y = -x - 4/3
Therefore, the slope of the equation is -1 and the y-intercept is -4/3.
The y-intercept as an ordered pair is (0, -4/3).