What is the slope and the y -intercept of the equation 9+272x=−32y . Write the y -intercept as an ordered pair.(1 point) The slope is . The y-intercept is ().
wrong
To find the slope and y-intercept, we need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Given equation: 9 + 272x = -32y
First, we need to isolate the y variable.
-32y = 9 + 272x
Now, we divide both sides of the equation by -32 to solve for y:
y = (9 + 272x) / -32
Simplifying further:
y = -9/32 - 17x/4
The slope (m) is the coefficient of x, which is -17/4.
The y-intercept (b) is the constant term, which is -9/32.
Therefore, the slope is -17/4 and the y-intercept is (-9/32, 0).
I apologize for the incorrect response. Let's find the correct slope and y-intercept.
Given equation: 9 + 272x = -32y
We need to isolate the y variable. First, let's subtract 9 from both sides:
272x = -32y - 9
Now, divide both sides by -32 to solve for y:
y = (272/(-32))x + (9/(-32))
Simplifying further:
y = -17/2x - 9/32
The slope (m) is the coefficient of x, which is -17/2.
The y-intercept (b) is the constant term, which is -9/32.
Therefore, the slope is -17/2 and the y-intercept is (0, -9/32).
9+27/2x=−3/2y .
To find the slope and y-intercept of the equation 9 + 272x = -32y, we need to rearrange the equation into slope-intercept form, which is of the form y = mx + b.
First, let's get the equation in slope-intercept form by solving for y:
9 + 272x = -32y
Divide both sides of the equation by -32:
(9 + 272x) / -32 = -32y / -32
-(9 + 272x) / 32 = y
Simplifying further:
y = -9/32 - 272x/32
y = -9/32 - 17x/4
Now we can identify the slope (m) and y-intercept (b).
The slope (m) is the coefficient of x, which is -17/4.
The y-intercept (b) is the constant term, which is -9/32.
So the slope is -17/4 and the y-intercept is (-9/32, 0).
To find the slope and y-intercept of the equation, we need to rewrite it in slope-intercept form, which is in the form y = mx + b, where m represents the slope and b represents the y-intercept.
Given equation: 9 + 272x = -32y
Step 1: Move the constants to the right side of the equation and rewrite the equation:
272x + 9 = -32y
Step 2: Divide the entire equation by -32 to isolate y:
(272x + 9)/-32 = y
Simplifying the equation, we have:
y = -(272x + 9)/32
Now that the equation is in slope-intercept form, we can determine the slope and y-intercept.
The slope, represented by m, is the coefficient of x. In this case, it is -272/32, which simplifies to -17/2.
The y-intercept, represented by (0, b), can be found by setting x = 0 in the equation:
y = -(272(0) + 9)/32
y = -9/32
So, the slope is -17/2, and the y-intercept is (0, -9/32).
To find the slope and y-intercept, we need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Given equation: 9 + 27/2x = -3/2y
First, we need to isolate the y variable.
-3/2y = 9 + 27/2x
Now, divide both sides of the equation by -3/2 to solve for y:
y = (9 + 27/2x) / (-3/2)
Simplifying further:
y = -2(9 + 27/2x) / 3
y = -18 - 27/2x
The slope (m) is the coefficient of x, which is -27/2.
The y-intercept (b) is the constant term, which is -18.
Therefore, the slope is -27/2 and the y-intercept is (0, -18).