Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5 . How far above or below street level is Luca’s initial launching point?(1 point)
Responses
2.5 feet below
2.5 feet below
5 feet below
5 feet below
0 feet above or below
0 feet above or below
5 feet above
The equation given is: y = -16t^2 + 40t - 5
To graph this equation in GeoGebra, follow these steps:
1. Open GeoGebra and create a new graphing window.
2. In the Input Bar at the bottom, type the equation: y = -16x^2 + 40x - 5
3. Press Enter or click the check mark button to graph the equation.
The graph will display a parabolic curve. The y-axis represents the height above or below street level, and the x-axis represents time. To determine how far above or below street level Luca's initial launching point is, look for the y-intercept of the graph.
In this case, the y-intercept occurs when x = 0. Plugging in x = 0 into the equation, we get:
y = -16(0)^2 + 40(0) - 5
y = 0 - 0 - 5
y = -5
Therefore, Luca's initial launching point is 5 feet below street level.