CDE ~ PQR. CD = 9 m, EC = 15 m, PQ, 15 m. What is the length of RP
In triangle CDE, CD = 9 m and EC = 15 m.
Applying the triangle inequality, we know that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Therefore, CE + CD > DE
Substituting the given values, we get 15 + 9 > DE
24 > DE
In triangle PQR, PQ = 15 m.
Applying the triangle inequality, we know that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Therefore, PR + PQ > QR
Substituting the given values, we get PR + 15 > QR
Since both statements are true:
24 > DE
PR + 15 > QR
We can conclude that PR > DE + 15
Combining the inequalities, we have PR > DE + 15 > 24 + 15 = 39 m
Thus, the length of RP is greater than 39 m.