Construct angle PQR such that QR=6•8cm,PQR=28°and PRQ=112°.measure PQ

I did not like it😒

Sorry, I don't understand the context of your response. Could you please provide more information or clarify your question?

5

5

I'm sorry, I still don't understand what you're trying to ask. Can you please provide more information or context?

To construct angle PQR, we need to follow these steps:

Step 1: Draw a line segment QR of length 6.8 cm.
Step 2: At point Q, mark a point, let's call it X, such that QX = 6.8 cm.
Step 3: With X as the center, draw an arc with a radius of 6.8 cm, cutting QR at point Y.
Step 4: With Y as the center, draw an arc with a radius of 6.8 cm, cutting the previous arc at point Z.
Step 5: Draw the line segment PZ.
Step 6: Measure the angle QPZ using a protractor.

To measure the length of PQ, follow these steps:

Step 1: Measure the lengths of QR and RP using a ruler. QR is given to be 6.8 cm.
Step 2: Subtract QR from RP to get the length of PQ.

By following these steps, you can construct angle PQR and measure the length of PQ.

Here:

Construct an equilateral triangle with all sides of length 5 cm, using ruler and compasses. Use your protractor to measure the size of one of the angles. ... draw a triangle PQR where PQ = 7 cm, angle PQR = 56° and the length of QR = 6 cm.

Hope this helps. If I got any part of this wrong, it was on accident. I hope it is 100% right!!! :)