Two bowling balls of different masses collide while accelerating at 1.875 m/s 2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses
13.125 N to the right
13.125 N to the right
8.875 N to the right
8.875 N to the right
7.5 N to the left
7.5 N to the left
3.73 N to the right
The force exerted by an object can be calculated using Newton's second law, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
For the first ball weighing 7 kg, the force exerted can be calculated as:
F1 = 7 kg * 1.875 m/s^2 = 13.125 N to the right
Therefore, the correct answer is 13.125 N to the right.