Two bowling balls of different masses collide while accelerating at 1.875 m/s^2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses
3.73 N to the right
3.73 N to the right
7.5 N to the left
7.5 N to the left
8.875 N to the right
8.875 N to the right
13.125 N to the right
To find the force exerted by the 7 kg ball on the 4 kg ball, we can use Newton's second law, which states that force equals mass times acceleration (F = m*a).
First, let's calculate the acceleration exerted by the 7 kg ball on the 4 kg ball. Since both balls are accelerating, the total acceleration is the sum of their individual accelerations, which are equal in magnitude but opposite in direction.
So, the total acceleration is 1.875 m/s^2 to the left (since the 4 kg ball is moving to the left).
Now, we can calculate the force exerted by the 7 kg ball on the 4 kg ball by using the second law.
F = m*a
F = (4 kg) * (-1.875 m/s^2)
F = -7.5 N
Since the force is negative, it means that the force exerted by the 7 kg ball on the 4 kg ball is directed to the left.
Therefore, the correct answer is:
7.5 N to the left
To find the force exerted by the 7 kg bowling ball on the 4 kg bowling ball, we can use Newton's second law of motion:
Force (F) = mass (m) * acceleration (a)
The mass of the 7 kg ball is 7 kg and the acceleration is 1.875 m/s^2. Substituting these values into the equation:
F = 7 kg * 1.875 m/s^2
F = 13.125 N
Therefore, the bowling ball weighing 7 kg exerts a force of 13.125 N to the right on the bowling ball weighing 4 kg.
To find the force exerted by the 7 kg bowling ball on the 4 kg bowling ball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
For the 7 kg bowling ball:
Mass (m1) = 7 kg
Acceleration (a) = 1.875 m/s^2
For the 4 kg bowling ball:
Mass (m2) = 4 kg
To calculate the force exerted by the 7 kg bowling ball on the 4 kg bowling ball, we can use the equation:
Force (F) = m1 * a
Substituting the values into the equation:
F = 7 kg * 1.875 m/s^2
F = 13.125 N
Therefore, the force exerted by the 7 kg bowling ball on the 4 kg bowling ball is 13.125 N to the right.