A bridge can hold a maximum of $75,000 lb a truck that weighs 40,000 lb carries boxes that weighs 40 lb each what is the maximum number of boxes the truck can carry to cross the bridge express your answer as an inequality
Let's assume the maximum number of boxes the truck can carry is represented by the variable $x$.
To find the maximum number of boxes the truck can carry, we need to find the weight of the truck and the weight of the boxes and ensure that it does not exceed the maximum weight the bridge can hold.
The weight of the truck is 40,000 lb, and the weight of each box is 40 lb. So the total weight of the boxes is $40x$ lb.
Therefore, we can write the inequality as:
$40,000 + 40x \leq 75,000$
Simplifying, we get:
$40x \leq 35,000$
Dividing both sides by 40, we find:
$x \leq 875$
Therefore, the maximum number of boxes the truck can carry to cross the bridge is 875.