a bridge can hold a maximum of 75,000 pounds a truck that weighs 40,000 pounds carries boxes that weigh 40 pounds each what is the maximum number of boxes the truck can carry to cross that bridge express your answer as an iniquity
To find the maximum number of boxes the truck can carry, we need to determine the weight of the truck and the boxes together.
The weight of the truck is given as 40,000 pounds.
Let's assume the truck can carry n boxes. Since each box weighs 40 pounds, the weight of the boxes would be 40 * n pounds.
So, the total weight of the truck and the boxes is 40,000 + (40 * n) pounds.
This total weight should be less than or equal to the maximum weight the bridge can hold, which is 75,000 pounds.
Therefore, the inequality we can set up is:
40,000 + (40 * n) ≤ 75,000
Simplifying this inequality, we have:
40,000 + 40n ≤ 75,000
Subtracting 40,000 from both sides of the inequality gives:
40n ≤ 35,000
Dividing both sides by 40, we get:
n ≤ 875
So, the maximum number of boxes the truck can carry to cross the bridge is 875.
-6n +3 _> 21 explain what the solution means
To solve the inequality -6n + 3 ≥ 21, we need to isolate the variable n.
Subtracting 3 from both sides of the inequality, we have:
-6n ≥ 18
Next, we divide both sides of the inequality by -6. When dividing by a negative number, we need to flip the inequality sign:
n ≤ -3
So, the solution to the inequality -6n + 3 ≥ 21 is n ≤ -3.
This means that any value of n that is less than or equal to -3 will make the inequality true. In other words, any number from negative infinity up to and including -3 will satisfy the inequality.