Function fis defined as f(x) = x2 + 17x + 60. What is the solution set for f(x) = 0?
To find the solution set for f(x) = 0, we need to solve the quadratic equation x^2 + 17x + 60 = 0.
We can factor the equation as follows:
(x + 12)(x + 5) = 0
Setting each factor equal to zero, we find two solutions:
x + 12 = 0 --> x = -12
x + 5 = 0 --> x = -5
Therefore, the solution set for f(x) = 0 is {-12, -5}.