Function f is defined as f(x)=x^2 + 17x + 60. What is the solution set for f(x)=0?
A. {5,12}
B.{-12, -5}
C. {-3,20}
D. {-20,3}
To solve f(x) = 0, we need to find the values of x that make the equation true. We can do this by factoring or by using the quadratic formula.
Using the quadratic formula, we have:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = 17, and c = 60. Plugging in these values, we get:
x = (-17 ± √(17^2 - 4(1)(60))) / 2(1)
x = (-17 ± √(289 - 240)) / 2
x = (-17 ± √49) / 2
x = (-17 ± 7) / 2
This gives us two possible values for x:
x = (-17 + 7) / 2 = -10 / 2 = -5
x = (-17 - 7) / 2 = -24 / 2 = -12
So the solution set for f(x) = 0 is {-12, -5}.
Therefore, the answer is B. {-12, -5}.