An organism has the genotype AaBbCc. What is the probability of producing a gamete that only has dominant alleles for these three genes?
To determine the probability of producing a gamete with only dominant alleles for these three genes, we need to consider the inheritance pattern of each individual gene.
If we assume that the genes A, B, and C are on separate chromosomes and segregate independently during gamete formation, we can use the principle of independent assortment to calculate the probability.
The genotype of the organism is AaBbCc, so we can break it down into the genotypes for each individual gene:
Gene A: Aa
Gene B: Bb
Gene C: Cc
To produce a gamete with only dominant alleles for Gene A, we need the gamete to carry allele A. Since the A gene is heterozygous Aa, there is a 1/2 chance of selecting allele A.
To produce a gamete with only dominant alleles for Gene B, we need the gamete to carry allele B. Since the B gene is heterozygous Bb, there is also a 1/2 chance of selecting allele B.
To produce a gamete with only dominant alleles for Gene C, we need the gamete to carry allele C. Since the C gene is heterozygous Cc, there is again a 1/2 chance of selecting allele C.
By multiplying the probabilities for each gene, we can calculate the overall probability:
1/2 (Gene A) x 1/2 (Gene B) x 1/2 (Gene C) = 1/8
Therefore, the probability of producing a gamete with only dominant alleles for these three genes is 1/8 (or 0.125).