A magnesium alloy contains the following volumes of each element: 341.2 cubic decimeters of magnesium, 30.96 cubic decimeters of aluminum, 488.0 cubic centimeters of manganese, and 672.0 cubic centimeters of zinc. Find the percent composition by volume of zinc. Round the answer to the nearest hundredth percent.
To find the percent composition by volume of zinc, we need to divide the volume of zinc by the total volume of the alloy and multiply by 100.
The total volume of the alloy is 341.2 + 30.96 + 488.0 + 672.0 = 1532.16 cubic decimeters.
The volume of zinc is 672.0 cubic centimeters, which is equivalent to 0.672 cubic decimeters.
The percent composition by volume of zinc is therefore (0.672 / 1532.16) * 100 = 0.0438 * 100 = 4.38%.
Rounded to the nearest hundredth percent, the answer is 4.38%. Answer: \boxed{4.38}.