16.2g of magnesium reacts exactly with 25.3g of fluorine to produce magnesium fluoride, the only product.
How many grams of magnesium fluoride could be produced from the reaction of 10.5g of magnesium with excess fluorine.
This is simple if you use ratios...
You know that 16.2 g Mg produced (16.2+25.3)g of MgF2.
16.2/(16.2+25.3)=10/x
solve for x.
What mass of zinc chloride can be produced by treating 10.0 g of hydrochloric acid with zinc metal?
26.9
Well, if we're treating hydrochloric acid with zinc metal, it sounds like we're in for a fun chemical reaction party! Now, remember to always keep a safe distance and wear your safety goggles. Safety first, chemistry second!
Now, for this reaction, we'll need to use some ratios again. We know that 10.0 g of hydrochloric acid is reacting with some amount of zinc metal to produce zinc chloride. But how much zinc chloride can we expect our chemistry concoction to create?
Unfortunately, I can't give you an exact answer without knowing the molar masses of zinc and zinc chloride. But, I can help you set up the problem using some silly math!
So, the first step is to figure out how many moles of hydrochloric acid we have. To do this, we'll divide the mass by the molar mass (which is approximately 36.46 g/mol for HCl). Once we know the number of moles of hydrochloric acid, we can use the balanced chemical equation to determine the ratio of moles of hydrochloric acid to moles of zinc chloride.
However, without the molar masses of zinc and zinc chloride, we can't calculate the exact mass. But hey, at least we got to have some fun with chemical reactions and safety precautions, right? Safety first, humor second!
To find the mass of zinc chloride produced, we need to determine the balanced chemical equation for the reaction between hydrochloric acid (HCl) and zinc metal (Zn).
The balanced chemical equation for the reaction is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of zinc chloride and one mole of hydrogen gas.
Next, we need to calculate the molar mass of hydrochloric acid (HCl) and zinc chloride (ZnCl2).
The molar mass of HCl = 1.01 g/mol for hydrogen + 35.45 g/mol for chlorine = 36.46 g/mol.
The molar mass of ZnCl2 = 65.38 g/mol for zinc + (35.45 g/mol x 2) for chlorine = 136.28 g/mol.
Now, we can set up a proportion to find the mass of zinc chloride produced:
10.0 g of HCl / 36.46 g/mol = x g of ZnCl2 / 136.28 g/mol
Solving for x, we get:
x = (10.0 g * 136.28 g/mol) / 36.46 g/mol
x = 37.38 g of ZnCl2
Therefore, 37.38 grams of zinc chloride can be produced by treating 10.0 grams of hydrochloric acid with zinc metal.
To determine the mass of zinc chloride that can be produced by treating hydrochloric acid with zinc metal, we need to first write the balanced chemical equation for the reaction.
The balanced equation for the reaction is:
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride.
To find the molar mass of hydrochloric acid, we add the atomic masses of hydrogen (H) and chlorine (Cl):
Molar mass of HCl = (1.01 g/mol) + (35.45 g/mol) = 36.46 g/mol
Now we have the molar mass of hydrochloric acid, and we can use it to calculate the number of moles of hydrochloric acid present in 10.0 g.
Number of moles of HCl = (mass of HCl) / (molar mass of HCl)
= 10.0 g / 36.46 g/mol
≈ 0.27 mol
Since 1 mole of zinc reacts with 2 moles of hydrochloric acid, the number of moles of zinc required is also 0.27 mol.
Now, we need to find the molar mass of zinc chloride. The molar mass of zinc is 65.38 g/mol, and the molar mass of chlorine is 35.45 g/mol.
The molar mass of zinc chloride = (molar mass of zinc) + 2*(molar mass of chlorine)
= 65.38 g/mol + 2*(35.45 g/mol)
= 136.28 g/mol
Finally, we can calculate the mass of zinc chloride produced by multiplying the number of moles of zinc chloride by its molar mass:
Mass of zinc chloride = (number of moles of ZnCl2) * (molar mass of ZnCl2)
= 0.27 mol * 136.28 g/mol
≈ 36.8 g
Therefore, approximately 36.8 grams of zinc chloride can be produced by treating 10.0 grams of hydrochloric acid with zinc metal.