A snack bar sells two sizes of snack packs. A large snack pack is $5 and a small pack is $3. In one day, the snack bar sold 60 packs for a total of $220. Write a system of equations that represents the scenario above. Let x = small packs and y = large snack packs. How many small packs did the snack bar sell? Use the elimination method to solve. (SOLVE FOR X)
The system of equations can be written as:
x = number of small packs
y = number of large packs
1) x + y = 60 (total number of packs sold)
2) 3x + 5y = 220 (total cost of packs sold)
To solve using the elimination method, we'll multiply equation 1 by 3:
3x + 3y = 180
3x + 5y = 220
Subtract equation 1 from equation 2:
(3x + 5y) - (3x + 3y) = 220 - 180
2y = 40
Divide both sides by 2:
2y/2 = 40/2
y = 20
Thus, the snack bar sold 20 large packs.