A snack bar sells two sizes of snack packs. A large snack pack is $5 and a small snack pack is $3. In one day the snack bar sold 60 snack packs for a total of $220.
Part A - Write a system of equations that represents the scenario above. Let X equal small snack packs and Y equal large snack packs.
Part B- How many small snack packs did the snack bar sell? Use the elimination method to solve.
Part A:
The total number of snack packs sold is 60:
X + Y = 60
The total amount earned from selling snack packs is $220:
3X + 5Y = 220
Part B:
To solve the system of equations, we can use the elimination method.
Multiply the first equation by 3:
3(X + Y) = 3(60)
3X + 3Y = 180
Subtract this equation from the second equation:
(3X + 5Y) - (3X + 3Y) = 220 - 180
2Y = 40
Divide both sides by 2:
Y = 20
Therefore, the snack bar sold 20 large snack packs.
how many small snack packs?
To find the number of small snack packs, substitute the value of Y (= 20) into the first equation:
X + 20 = 60
Subtract 20 from both sides:
X = 40
Therefore, the snack bar sold 40 small snack packs.