Two bowling balls of different masses collide while accelerating at 1.875 m/s 2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
8.875 N to the right
8.875 N to the right
7.5 N to the left
7.5 N to the left
3.73 N to the right
3.73 N to the right
13.125 N to the right
To solve this problem, we can use Newton's second law of motion, which states that the force exerted on an object is equal to its mass multiplied by its acceleration. In this case, the acceleration is given as 1.875 m/s^2.
The force exerted by the first ball (7 kg) can be calculated as:
Force1 = mass1 * acceleration
Force1 = 7 kg * 1.875 m/s^2
Force1 = 13.125 N to the right
The force exerted by the second ball (4 kg) can be calculated in the same way:
Force2 = mass2 * acceleration
Force2 = 4 kg * 1.875 m/s^2
Force2 = 7.5 N to the left
Therefore, the bowling ball weighing 7 kg exerts a force of 13.125 N to the right on the bowling ball weighing 4 kg.
The correct answer is "13.125 N to the right."