There are two types of tickets to attend and it awards dinner, silver and gold The gold tickets are eight dollars more than the silver if Patrick bought 10 tickets at each level and spent a total of $140 find the price of each ticket
Let's assume the price of the silver ticket is "x" dollars.
According to the given information, the price of the gold ticket would be "x + 8" dollars.
If Patrick bought 10 silver tickets, the total cost of silver tickets would be 10x dollars.
Similarly, if Patrick bought 10 gold tickets, the total cost of gold tickets would be 10(x + 8) dollars.
The total cost of all tickets is given as $140, so we can set up the equation:
10x + 10(x + 8) = 140
Simplify the equation:
10x + 10x + 80 = 140
Combine like terms:
20x + 80 = 140
Subtract 80 from both sides:
20x = 60
Divide by 20:
x = 3
So, the price of a silver ticket is $3.
The price of the gold ticket would be 3 + 8 = $<<3+8=11>>11. Answer: \boxed{3, 11}.