There are 2 types of tickets to attend an awards dinner silver and gold The gold tickets are $8 more than silver if Patrick bought 10 tickets at each level and spent a total of $140, find the price of each ticket.
Let the price of a silver ticket be x dollars.
Therefore, the price of a gold ticket is x + $8.
Patrick bought 10 silver tickets, so he spent 10x dollars.
He also bought 10 gold tickets, so he spent 10(x + $8) dollars.
The total amount he spent is $140, so 10x + 10(x + $8) = $140.
Expanding the equation, we get 10x + 10x + $80 = $140.
Combining like terms, we get 20x + $80 = $140.
Subtracting $80 from both sides of the equation, we get 20x = $60.
Dividing both sides of the equation by 20, we get x = $3.
Therefore, the price of a silver ticket is $3.
The price of a gold ticket is x + $8 = $3 + $8 = $ <<3+8=11>>11. Answer: \boxed{11}.