Two bowling balls of different masses collide while accelerating at 1.875 m/s2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses
13.125 N to the right
13.125 N to the right
7.5 N to the left
7.5 N to the left
8.875 N to the right
8.875 N to the right
3.73 N to the right
3.73 N to the right
To solve this problem, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Let's calculate the force exerted by the 7 kg bowling ball:
F = m * a
F = 7 kg * 1.875 m/s^2
F = 13.125 N
Since the bowling ball weighing 7 kg is rolling to the right and colliding with the bowling ball weighing 4 kg, the force it exerts on the 4 kg ball would also be to the right. Therefore, the correct answer is:
13.125 N to the right.