A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at a speed of 12 m/s, what is the person’s kinetic energy? Hint: Use the formula KE=½ mv2
To find the person's kinetic energy, we can use the formula KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass of the person, and v is the speed at which they reach the water.
Given:
m = 45 kg (mass of the person)
v = 12 m/s (speed at which they reach the water)
Plugging these values into the formula, we get:
KE = 1/2 * 45 kg * (12 m/s)^2
Simplifying the expression within the parentheses, we get:
KE = 1/2 * 45 kg * 144 m^2/s^2
Multiplying the numbers, we have:
KE = 0.5 * 45 kg * 144 m^2/s^2
Calculating the product, we find:
KE = 3240 kg * m^2/s^2
Thus, the person's kinetic energy is 3240 kg * m^2/s^2.