A 45 kg person jumps off a diving platform 10.0 m above the water. If they reaches the surface of the water at a speed of 12 m/s, what is the person’s kinetic energy? Hint: Use the formula KE=½ mv2(3 points)
The formula for kinetic energy is KE=½ mv², where m is the mass of the object and v is the velocity of the object.
Given:
m = 45 kg (mass of the person)
v = 12 m/s (speed of the person)
Substituting the given values into the formula, we get:
KE = ½ (45 kg) (12 m/s)²
= ½ (45 kg) (144 m²/s²)
= 0.5 (45 kg) (144 m²/s²)
= 0.5 (6480 kg m²/s²)
= 3240 kg m²/s²
Therefore, the person's kinetic energy is 3240 kg m²/s².
To find the person's kinetic energy, we can use the formula:
KE = ½ mv^2
Where:
KE is the kinetic energy
m is the mass of the person
v is the velocity of the person
Given:
m = 45 kg (mass of the person)
v = 12 m/s (velocity of the person)
Now, we can substitute the given values into the formula:
KE = ½ (45 kg) (12 m/s)^2
Simplifying the equation:
KE = ½ (45) (144)
KE = 0.5 * 45 * 144
KE = 3240 J
Therefore, the person's kinetic energy is 3240 Joules.
To find the person's kinetic energy, we can use the formula KE = ½mv^2, where KE represents kinetic energy, m represents mass in kg, and v represents velocity in m/s.
The question provides the mass of the person as 45 kg and the velocity at which they reach the water as 12 m/s.
Now we can substitute these values into the formula to calculate the kinetic energy.
KE = ½ * 45 kg * (12 m/s)^2
KE = ½ * 45 * 144
KE = 0.5 * 45 * 144
KE = 3240
Therefore, the person's kinetic energy is 3240 J (Joules).
Please note that in this calculation we have assumed that there are no other factors affecting the kinetic energy, such as air resistance.