Find the distance between (-8, - 3) and (-2, - 5). Round your answer to the nearest hundredth, if necessary.

(1 point)

Using the distance formula, the distance between (-8, - 3) and (-2, - 5) is calculated as follows:

√[(x2 - x1)² + (y2 - y1)²]
= √[(-2 - (-8))² + (-5 - (-3))²]
= √[6² + (-2)²]
= √[36 + 4]
= √40

The square root of 40 is approximately 6.32 (rounded to the nearest hundredth). Therefore, the distance between (-8, - 3) and (-2, - 5) is approximately 6.32.

To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Let's plug in the coordinates:

x1 = -8
y1 = -3
x2 = -2
y2 = -5

Substituting these values, we get:

d = sqrt((-2 - (-8))^2 + (-5 - (-3))^2)

Simplifying further,

d = sqrt((-2 + 8)^2 + (-5 + 3)^2)

d = sqrt((6)^2 + (-2)^2)

d = sqrt(36 + 4)

d = sqrt(40)

Now, rounding the answer to the nearest hundredth, we get:

d ≈ 6.32

Therefore, the distance between (-8, -3) and (-2, -5) is approximately 6.32 units.

Wrong

To find the distance between two points on a coordinate plane, you can use the distance formula. The distance formula is derived from the Pythagorean theorem.

The formula to find the distance between two points (x1, y1) and (x2, y2) is:

d = √((x2 - x1)^2 + (y2 - y1)^2)

In this case, the coordinates of the first point are (-8, -3) and the coordinates of the second point are (-2, -5).

Plugging the values into the formula, we get:

d = √((-2 - (-8))^2 + (-5 - (-3))^2)

Simplifying further:

d = √((6)^2 + (-2)^2)

d = √(36 + 4)

d = √40

Now, we can round the answer to the nearest hundredth:

d ≈ 6.32

Therefore, the distance between (-8, -3) and (-2, -5) is approximately 6.32.

Apologies for the mistake. Let's correct the calculation:

Using the distance formula, the distance between (-8, -3) and (-2, -5) is calculated as follows:

√[(x2 - x1)² + (y2 - y1)²]
= √[(-2 - (-8))² + (-5 - (-3))²]
= √[(6)² + (-2)²]
= √[36 + 4]
= √40

To the nearest hundredth, √40 is approximately 6.32.

Therefore, the distance between (-8, -3) and (-2, -5) is approximately 6.32 units.