Find the distance between (−8, −3) and (−2, −5) . Round your answer to the nearest hundredth, if necessary.(1 point)
Using the distance formula, the distance between (-8, -3) and (-2, -5) is:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
= sqrt((-2 - (-8))^2 + (-5 - (-3))^2)
= sqrt((-2 + 8)^2 + (-5 + 3)^2)
= sqrt(6^2 + (-2)^2)
= sqrt(36 + 4)
= sqrt(40)
≈ 6.32
Rounded to the nearest hundredth, the distance is approximately 6.32.
To find the distance between two points (x1, y1) and (x2, y2), you can use the distance formula:
d = √[(x2 - x1)^2 + (y2 - y1)^2]
Given the points (-8, -3) and (-2, -5), we can substitute the values into the formula:
d = √[(-2 - (-8))^2 + (-5 - (-3))^2]
Simplifying:
d = √[(-2 + 8)^2 + (-5 + 3)^2]
= √[6^2 + (-2)^2]
= √[36 + 4]
= √40
Rounding the answer to the nearest hundredth:
d ≈ 6.32
Therefore, the distance between (-8, -3) and (-2, -5) is approximately 6.32.
To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
𝑑 = √((𝑥2 - 𝑥1)² + (𝑦2 - 𝑦1)²)
Let's label the coordinates of the first point as (𝑥1, 𝑦1) = (−8, −3) and the coordinates of the second point as (𝑥2, 𝑦2) = (−2, −5).
Now, substitute the values into the distance formula:
𝑑 = √((−2 - (−8))² + (−5 - (−3))²)
Simplifying inside the square root:
𝑑 = √((−2 + 8)² + (−5 + 3)²)
𝑑 = √(6² + (-2)²)
𝑑 = √(36 + 4)
𝑑 = √40
𝑑 = 6.32
Therefore, the distance between (−8, −3) and (−2, −5) is approximately 6.32, rounded to the nearest hundredth.