A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?(1 point)
Responses
The acceleration decreases to a quarter of its original value, or about 2.13 m/s2.
The acceleration decreases to a quarter of its original value, or about 2.13 m/s 2 .
The acceleration increases to four times its original value, or about 2.13 m/s2.
The acceleration increases to four times its original value, or about 2.13 m/s 2 .
The acceleration increases to four times its original value, or about 0.13 m/s2.
The acceleration increases to four times its original value, or about 0.13 m/s 2 .
The acceleration decreases to a quarter of its original value, or about 0.13 m/s2.
The acceleration decreases to a quarter of its original value, or about 0.13 m/s2.
The acceleration decreases to a quarter of its original value, or about 0.13 m/s2.
To determine the effect of changing the net force on the acceleration of the object, we can use Newton's second law of motion:
F = m * a
where F is the net force, m is the mass, and a is the acceleration. Rearranging the formula, we can solve for acceleration:
a = F / m
Given that the original net force is 0.8 N and the original mass is 1.5 kg, we can calculate the original acceleration:
a = 0.8 N / 1.5 kg = 0.533 m/s^2
Now, let's see what happens when the net force is decreased to 0.2 N while the mass remains the same:
a = 0.2 N / 1.5 kg = 0.133 m/s^2
Comparing the two accelerations, we can see that the new acceleration is indeed smaller. In fact, the new acceleration is approximately one-fourth (or a quarter) of the original acceleration. Therefore, the correct answer is:
The acceleration decreases to a quarter of its original value, or about 0.13 m/s^2.