A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?(1 point) Responses
\
The acceleration of the object would decrease.
This is because the net force applied to an object is directly proportional to its acceleration according to Newton's second law of motion. Therefore, if the net force is decreased, the acceleration of the object would also decrease.
To determine what happens to the acceleration of the object when the net force is decreased, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula for Newton's second law is:
F = m * a
Where:
F = net force
m = mass
a = acceleration
Given that the net force is decreased from 0.8 N to 0.2 N, and the mass is 1.5 kg, we can plug these values into the formula to find the acceleration.
For the initial net force of 0.8 N:
a1 = F1 / m
a1 = 0.8 N / 1.5 kg
For the decreased net force of 0.2 N:
a2 = F2 / m
a2 = 0.2 N / 1.5 kg
Now we can solve for the values of a1 and a2:
a1 = 0.8 N / 1.5 kg = 0.533 m/s^2
a2 = 0.2 N / 1.5 kg = 0.133 m/s^2
By comparing the two accelerations, we can see that the acceleration of the object decreases from 0.533 m/s^2 to 0.133 m/s^2 when the net force is decreased from 0.8 N to 0.2 N.
To determine what happens to the acceleration of the object when the net force is decreased to 0.2 N, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law of motion is:
F = m * a
Where:
F = force acting on the object (in newtons)
m = mass of the object (in kilograms)
a = acceleration of the object (in meters per second squared)
In the given scenario, the net force acting on the 1.5 kg mass is initially 0.8 N. Thus, we can solve for the initial acceleration (a1) using the formula:
0.8 N = 1.5 kg * a1
Solving for a1, we get:
a1 = 0.8 N / 1.5 kg
a1 ≈ 0.53 m/s²
Now, we need to determine the new acceleration (a2) when the net force is decreased to 0.2 N. Using the same formula as before, but with the new force value, we can calculate a2:
0.2 N = 1.5 kg * a2
Solving for a2, we get:
a2 = 0.2 N / 1.5 kg
a2 ≈ 0.13 m/s²
Therefore, when the net force acting on the object decreases to 0.2 N, the acceleration of the object decreases to approximately 0.13 m/s².