Two compounds of phosphorous and fluorine have the following mass ratio
Compound 1: 10.14 g fluorine for every 3.38 g phosphorus
Compound 2: 8.42 g fluorine for every 4.21 g phosphorus
Find the whole number ratio of masses of fluorine in Compound 1 and Compound 2
To find the whole number ratio of masses of fluorine in Compound 1 and Compound 2, we can divide the mass of fluorine in Compound 1 by the mass of fluorine in Compound 2.
The mass of fluorine in Compound 1 is 10.14 g.
The mass of fluorine in Compound 2 is 8.42 g.
Dividing the mass of fluorine in Compound 1 by the mass of fluorine in Compound 2, we get:
10.14 g / 8.42 g ≈ 1.203
Therefore, the whole number ratio of masses of fluorine in Compound 1 and Compound 2 is 1:1.
To find the whole number ratio of masses of fluorine in Compound 1 and Compound 2, we need to compare the mass of fluorine in both compounds.
Compound 1: 10.14 g fluorine for every 3.38 g phosphorus
Compound 2: 8.42 g fluorine for every 4.21 g phosphorus
To make the comparison easier, we can divide the mass of fluorine by the mass of phosphorus in each compound:
Compound 1: 10.14 g F / 3.38 g P = 3
Compound 2: 8.42 g F / 4.21 g P = 2
The whole number ratio of masses of fluorine in Compound 1 to Compound 2 is 3:2.
To find the whole number ratio of the masses of fluorine in Compound 1 and Compound 2, we need to determine the relative masses of fluorine in each compound.
Let's calculate the relative masses of fluorine in Compound 1 and Compound 2.
Relative mass of fluorine in Compound 1 = Mass of fluorine in Compound 1 / Mass of phosphorus in Compound 1
Relative mass of fluorine in Compound 1 = 10.14 g / 3.38 g
Relative mass of fluorine in Compound 1 ≈ 3
Relative mass of fluorine in Compound 2 = Mass of fluorine in Compound 2 / Mass of phosphorus in Compound 2
Relative mass of fluorine in Compound 2 = 8.42 g / 4.21 g
Relative mass of fluorine in Compound 2 ≈ 2
Therefore, the whole number ratio of the masses of fluorine in Compound 1 and Compound 2 is 3:2.