Determine the ph
[H30+] = 2×10^-4 M
Express your answer using one decimal place.
The pH can be determined using the formula:
pH = -log[H30+]
Substituting the given value of [H30+] into the formula:
pH = -log(2×10^-4)
Using a calculator, the pH is approximately 3.7.
To determine the pH, we can use the equation:
pH = -log[H3O+]
Given that [H3O+] = 2×10^-4 M, we can substitute it into the equation:
pH = -log(2×10^-4)
Now, let's calculate the pH:
pH = -log(2×10^-4)
pH = -log(2) - log(10^-4)
Since log(10^-4) = -4, we can simplify further:
pH = -log(2) - (-4)
pH = -log(2) + 4
Next, we need to calculate the logarithm of 2, which can be done using a calculator:
log(2) ≈ 0.3010
Substituting this value back into the equation:
pH ≈ -0.3010 + 4
pH ≈ 3.7
Therefore, the pH is approximately 3.7.
To determine the pH, you can use the following formula:
pH = -log[H3O+]
Given that [H3O+] = 2×10^-4 M, you can plug this value into the formula:
pH = -log(2×10^-4)
Now, let's calculate the pH using a calculator or by using logarithmic properties:
pH = -log(2×10^-4)
= -log(2) + log(10^-4)
= -log(2) - 4
Using a calculator, we can find that log(2) is approximately 0.3010. Substituting this value into the equation:
pH = -0.3010 - 4
= -4.3010
Finally, since the question asks for the answer to be expressed using one decimal place, we can round the pH value to one decimal place:
pH ≈ -4.3
Therefore, the pH of the solution with [H3O+] = 2×10^-4 M is approximately -4.3.