Niel has a bucket of beads. He uses them to make 8 identical necklaces and then buys 25 beads at the store. He ends up with a total of 500 beads. How many did he start with? Identify the operations needed to solve this problem using the equation b8 + 25 = 500 .(1 point) Responses addition and division addition and division addition and multiplication addition and multiplication subtraction and multiplication subtraction and multiplication subtraction and division

The correct operations needed to solve this problem using the equation b8 + 25 = 500 are addition and division.

The correct operations needed to solve this problem using the equation b8 + 25 = 500 are addition and division.

To solve this problem, we can use addition and subtraction operations along with division.

Let's break down the problem step by step:
1. Niel used the beads to make 8 identical necklaces, which means he used 8 times the number of beads for one necklace. So, we can multiply the number of beads for one necklace by 8: n * 8.
2. After making the necklaces, Niel bought 25 more beads at the store. We can add these 25 beads to the previous result: n * 8 + 25.
3. The total number of beads Niel ended up with is 500, which can be set as equal to the previous result: n * 8 + 25 = 500.

So, to solve this problem, we need to use the equation n * 8 + 25 = 500, where n represents the number of beads Niel started with. By rearranging the equation, we can calculate the value of n.

Now, we can solve the equation using the operations mentioned earlier: addition and subtraction along with division.

Here's how:
1. Start with the equation: n * 8 + 25 = 500.
2. First, subtract 25 from both sides to isolate the n * 8 term: n * 8 = 500 - 25.
3. Simplify the right-hand side: n * 8 = 475.
4. To find the value of n, divide both sides by 8: n = 475 / 8.
5. The quotient of 475 divided by 8 is 59.375.

Therefore, Niel started with approximately 59.375 beads. Since beads are typically whole numbers, we can assume that he started with 59 beads, rather than a fractional amount.