Use the equation to answer the question. CH4 + 2O2 → CO2 + 2H2O If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation?
There is an extra O2 molecule left over. There is an extra cap o sub 2 molecule left over. There are now 3H2O molecules. There are now 3 cap h sub 2 cap o molecules. Nothing changes in the equation. Nothing changes in the equation. There are now 3CO2 molecules.
If you change the 2 in front of 2O2 to a 3, the change in the results on the right side of the equation will be that there are now 3CO2 molecules.
If you change the coefficient in front of 2O2 to 3, the change in the results on the right side of the equation would be: There are now 3CO2 molecules.
To answer this question, we need to understand the balanced chemical equation provided:
CH4 + 2O2 → CO2 + 2H2O
In this equation, CH4 represents methane, O2 represents oxygen, CO2 represents carbon dioxide, and H2O represents water.
The coefficient in front of each molecule indicates the number of moles of each substance involved in the reaction.
When we change the coefficient in front of O2 from 2 to 3, the equation becomes:
CH4 + 3O2 → CO2 + 2H2O
Since the equation is balanced, any change in the coefficients will also require adjustments to maintain balance.
Comparing the two equations, we can see that the change in the results on the right side of the equation is:
- There is an extra O2 molecule left over.
Therefore, the correct answer to the question is: "There is an extra O2 molecule left over."