Which of the following equations demonstrates the Law of Conservation of Mass? (1 point) Responses CH4+O2→CO2+HO CH4+O2→C+2H2O CH+O2→CO2+H2O CH4+O2→CO2+H2O
The equation that demonstrates the Law of Conservation of Mass is: CH4+O2→CO2+2H2O
The equation that demonstrates the Law of Conservation of Mass is CH4+O2→CO2+2H2O.
The Law of Conservation of Mass states that mass is neither created nor destroyed in a chemical reaction. In order to determine which of the given equations demonstrates this law, we need to calculate the total mass of the reactants and compare it to the total mass of the products.
Let's break down each equation and calculate the total mass for both sides:
1. CH4 + O2 → CO2 + HO
Total mass of the reactants: 1 carbon (12.01 g) + 4 hydrogen (4.03 g) + 2 oxygen (32.00 g) = 52.07 g
Total mass of the products: 1 carbon (12.01 g) + 2 oxygen (32.00 g) + 1 hydrogen (1.01 g) + 1 oxygen (16.00 g) = 61.02 g
2. CH4 + O2 → C + 2H2O
Total mass of the reactants: 1 carbon (12.01 g) + 4 hydrogen (4.03 g) + 2 oxygen (32.00 g) = 52.07 g
Total mass of the products: 1 carbon (12.01 g) + 4 hydrogen (4.03 g) + 4 hydrogen (4.03 g) + 1 oxygen (16.00 g) = 36.07 g
3. CH + O2 → CO2 + H2O
Total mass of the reactants: 1 carbon (12.01 g) + 1 hydrogen (1.01 g) + 2 oxygen (32.00 g) = 45.02 g
Total mass of the products: 1 carbon (12.01 g) + 2 oxygen (32.00 g) + 1 hydrogen (1.01 g) + 1 oxygen (16.00 g) = 61.02 g
4. CH4 + O2 → CO2 + H2O
Total mass of the reactants: 1 carbon (12.01 g) + 4 hydrogen (4.03 g) + 2 oxygen (32.00 g) = 52.07 g
Total mass of the products: 1 carbon (12.01 g) + 2 oxygen (32.00 g) + 1 carbon (12.01 g) + 2 hydrogen (2.02 g) + 1 oxygen (16.00 g) = 74.04 g
By comparing the total mass of the reactants and the total mass of the products for each equation, we can see that the equation that demonstrates the Law of Conservation of Mass is:
CH4 + O2 → CO2 + H2O
In this equation, the total mass of the reactants (52.07 g) is equal to the total mass of the products (52.06 g), following the Law of Conservation of Mass.