Moira needs a total of 214 hours to finish reading a book. Yesterday, she read for 1 7/8 hours. Supply the correct numbers to complete the equation that can be used to determine the number of hours, h , that Moira needs to read to finish the book.

To determine the number of hours Moira needs to read to finish the book, we can set up the equation:

Total hours needed - hours already read = hours Moira needs to read

Total hours needed = 214 hours
Hours already read = 1 7/8 hours

To subtract the mixed number 1 7/8, we need to convert it to an improper fraction:

1 7/8 = (8 * 1 + 7)/8 = 15/8

Now we can substitute the given values into the equation:

214 - 15/8 = h

Simplifying the equation further:

214 - 15/8 = h
1712/8 - 15/8 = h
(1712 - 15)/8 = h
1697/8 = h

Therefore, Moira needs to read for 1697/8 or 212 1/8 hours to finish the book.

To determine the number of hours Moira needs to read to finish the book, we can subtract the time she has already read from the total time needed.

Let's break down the information provided:
Total hours needed to finish the book = 214 hours
Time she read yesterday = 1 7/8 hours

To subtract a mixed number, we need to convert it into an improper fraction. The improper fraction equivalent of 1 7/8 is (8 * 1 + 7) / 8 = 15/8.

Now we can set up the equation:
Remaining hours = Total hours needed - Time she has already read

h (unknown number of hours) = 214 hours - 15/8 hours

To simplify the equation, we need a common denominator for subtraction. The least common multiple of 8 and 1 is 8.

h = (214 * 8/8) - (15/8)
h = 1712/8 - 15/8

Now, we can subtract the numerators:
h = (1712 - 15) / 8
h = 1697/8

Therefore, the equation to determine the number of hours, h, Moira needs to read to finish the book is:
h = 1697/8 hours.

The equation that can be used to determine the number of hours that Moira needs to read to finish the book is:

1 7/8 + h = 214

We add 1 7/8 to h (the number of hours Moira still needs to read) and set it equal to 214 (the total number of hours needed to finish the book).