Multiply 9√3*6√7. Give an exact answer
To multiply 9√3 and 6√7, we can multiply the coefficients (9*6) and multiply the radicals (√3*√7).
The product of the coefficients is:
9 * 6 = 54.
The product of the radicals is:
√3 * √7 = √(3 * 7) = √21.
Thus, the exact answer is 54√21.
To multiply √3 and √7, you can simply multiply the numbers outside the square roots together and keep the square roots separate. So, 9√3 * 6√7 becomes:
9 * 6 * √3 * √7
Now, multiply the numbers outside the square roots together:
54 * √3 * √7
To simplify further, combine the square roots:
54 * √(3*7)
54 * √21
Therefore, the exact answer is 54√21
To find the product of two numbers with square roots, we can multiply the numbers outside the square roots together, and then multiply the numbers inside the square roots together.
In this case, we have (9√3) * (6√7).
First, let's multiply the numbers outside the square roots: 9 * 6 = 54.
Next, let's multiply the numbers inside the square roots: √3 * √7 = √(3 * 7) = √21.
So the product of 9√3 and 6√7 is 54√21.