A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)
10−30h=0 10 minus 30 h equals 0 30h=10 30 h equals 10 1,280+30h=0 1,280 plus 30 h equals 0 1,280−30h=0
The correct equation to show how long the water in the cooler will last is:
1,280 - 30h = 0
The correct equation to show how long the water in the cooler will last is:
1,280 - 30h = 0
Where:
1,280 represents the initial amount of water in the cooler (10 gallons = 1,280 ounces)
30 represents the amount of water removed from the cooler every hour
h represents the number of hours that the water will last.
To write an equation to show how long the water in the cooler will last, we need to consider the amount of water being consumed each hour.
Given that 30 ounces of water are removed each hour, we can calculate how many hours it will take to consume all the water in the 10-gallon (1,280 ounces) cooler.
Let's use the variable 'h' to represent the number of hours.
Since the water is being consumed, we need to subtract the amount of water consumed (30 ounces) from the initial amount of water (1,280 ounces) in each hour:
1,280 - 30h = 0
This equation states that the remaining amount of water (1,280 - 30h) will eventually reach zero, indicating that all the water has been consumed.
Simplifying the equation further:
30h = 1,280
This equation indicates that the time it takes to consume all the water (30h) will equal 1,280 ounces.
Therefore, the equation to show how long the water in the cooler will last is:
1,280 - 30h = 0