A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point) Responses 1,280+30h=0 1,280 plus 30 h equals 0 30h=10 30 h equals 10 10−30h=0 10 minus 30 h equals 0 1,280−30h=0
1,280 - 30h = 0
The correct equation to show how long the water in the cooler will last is:
1,280 - 30h = 0
To write an equation that shows how long the water in the cooler will last, we need to consider the amount of water removed from the cooler each hour and the initial amount of water in the cooler.
The initial amount of water in the cooler is 10 gallons, which is equivalent to 1,280 ounces.
Each hour, 30 ounces of water are removed from the cooler.
Let's choose 'h' to represent the number of hours that have passed.
The amount of water remaining in the cooler after 'h' hours can be represented as:
Initial amount of water - Amount of water removed each hour * Number of hours = 1,280 - 30h
Therefore, the equation to show how long the water in the cooler will last is:
1,280 - 30h = 0
So, the correct equation is: 1,280 - 30h = 0.