you ride your bike at a constant speed of 12 m/s for 100 s from your house to the mailbox. what was your acceleration for the trip
a=(Vf-Vi)/t
8.33 m/s^2
0.58 m/s^2
0 m/s^2
120 m/s^2
The acceleration for the trip is 0 m/s^2.
Acceleration is defined as the change in velocity divided by the change in time. In this case, the velocity remains constant at 12 m/s for the entire trip, so there is no change in velocity. Therefore, the acceleration is 0 m/s^2.
To find the acceleration for the trip, we can use the formula:
acceleration (a) = (final velocity (Vf) - initial velocity (Vi)) / time (t)
Given that the constant speed is 12 m/s and the time taken is 100 s, we can substitute the values into the formula:
Acceleration (a) = (12 m/s - 12 m/s) / 100 s
Acceleration (a) = 0 m/s^2
Therefore, the acceleration for the trip is 0 m/s^2.
To determine the acceleration for the trip, you can use the formula:
Acceleration (a) = (Final velocity (Vf) - Initial velocity (Vi)) / Time (t)
In this case, we have the following values:
Vi = 0 m/s (assuming you started from rest)
Vf = 12 m/s (constant speed)
t = 100 s
Using the equation, we can calculate the acceleration as follows:
a = (12 m/s - 0 m/s) / 100 s
a = 0.12 m/s / s
a = 0.12 m/s^2
Therefore, the acceleration for the trip is 0.12 m/s^2. None of the answer choices provided match this value, so none of the options provided are correct.