you ride your bike at a constant speed of 12 m/s for 100 s from your house to the mailbox. what was your acceleration for the trip
a=(Vf-Vi)/t
In this case, since the speed is constant, the final velocity (Vf) is equal to the initial velocity (Vi). Therefore, the numerator of the equation (Vf - Vi) is equal to 0, and the acceleration (a) would be 0 as well.
To calculate the acceleration for the trip, we can use the formula:
acceleration (a) = (final velocity (Vf) - initial velocity (Vi)) / time (t)
In this case, the initial velocity (Vi) is 0 m/s because you start from rest. The final velocity (Vf) is 12 m/s because you ride your bike at a constant speed of 12 m/s. The time (t) is 100 seconds as given in the question.
Substituting these values into the formula, we get:
acceleration (a) = (12 m/s - 0 m/s) / 100 s
Simplifying further:
acceleration (a) = 12 m/s / 100 s
Now, we can divide to find the answer:
acceleration (a) = 0.12 m/s²
Therefore, the acceleration for the trip from your house to the mailbox is 0.12 m/s².
To find the acceleration, we need to calculate the change in velocity and divide it by the time taken. In this case, the initial velocity (Vi) is 0 m/s because you start from rest. The final velocity (Vf) is 12 m/s. The time taken (t) is 100 seconds.
Using the formula:
acceleration (a) = (Vf - Vi) / t
Substituting the values:
a = (12 m/s - 0 m/s) / 100 s
Simplifying the equation:
a = 12 m/s / 100 s
Dividing the numerator and denominator:
a = 0.12 m/s²
Therefore, your acceleration for the trip is 0.12 m/s².