Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0 ? Why?(1 point)
To determine if (-2, 6) is a solution to the system of equations, we substitute the values of x and y into both equations and check if the equations are satisfied.
For the first equation:
x + 2y = 10
(-2) + 2(6) = 10
-2 + 12 = 10
10 = 10
For the second equation:
3x + y = 0
3(-2) + 6 = 0
-6 + 6 = 0
0 = 0
In both cases, the equations are true, so (-2, 6) is indeed a solution to the system of linear equations.
Yes, because the graphs don’t intersect at (−2, 6).
Yes, because the graphs intersect at (−2, 6).
No, because the graphs don’t intersect at (−2, 6).
No, because the graphs intersect at (−2, 6).
Yes, because the graphs intersect at (−2, 6).
Estimate the solution to the system of these linear equations based on the graph.y=5x+10 y=−2x+3 (1 point)
Based on the graph of the equations y=5x+10 and y=−2x+3, it appears that the two lines intersect at a point near (1, 15). Therefore, the estimate for the solution to the system of linear equations is (1, 15).
(1, 5)
(5,−1)
(−1, 5)
(−1,−5)
The estimate for the solution to the system of linear equations based on the graph is (1, 5).
What is the last step to solving a system of equations by substitution?
Estimate the intersection point.
Graph the lines.
Make a table of solutions of the linear equations.
Check the answer.