evaluate the expression 5x^2+2y when x=-3 and y = 0.25
To evaluate the expression 5x^2 + 2y when x = -3 and y = 0.25, we substitute the given values into the expression:
5(-3)^2 + 2(0.25)
Simplifying, we start by calculating the square of -3:
(-3)^2 = 9
Next, we multiply 5 by 9:
5 * 9 = 45
Then, we multiply 2 by 0.25:
2 * 0.25 = 0.5
Finally, we add 45 and 0.5:
45 + 0.5 = 45.5
Therefore, when x = -3 and y = 0.25, the expression 5x^2 + 2y evaluates to 45.5.
To evaluate the expression 5x^2 + 2y when x = -3 and y = 0.25, substitute the given values into the expression.
Replace x with -3 and y with 0.25:
5(-3)^2 + 2(0.25)
Simplify:
5(9) + 0.5
Multiply:
45 + 0.5
Add:
45.5
Therefore, when x = -3 and y = 0.25, the expression 5x^2 + 2y is equal to 45.5.
To evaluate the expression 5x^2 + 2y when x = -3 and y = 0.25, we substitute the given values of x and y into the expression.
Step 1: Substitute x = -3 and y = 0.25 into the expression.
5(-3)^2 + 2(0.25)
Step 2: Simplify the exponents and perform the calculations inside the parentheses.
5(9) + 0.5
Step 3: Multiply the coefficient and the number inside the parentheses.
45 + 0.5
Step 4: Perform the addition.
45.5
Therefore, when x = -3 and y = 0.25, the expression 5x^2 + 2y evaluates to 45.5.