An average American household uses about 1.04×10^4 kWh (kilowatt hours) of electricity a year. If a power station generates 2.496×10^10 kWh per year, how many households can it serve? Write your answer in scientific notation, expressed to the exact decimal place.(1 point)
To find out how many households can be served by the power station, we need to divide the total electricity generated by the power station by the electricity used by an average household.
Total electricity generated by the power station = 2.496 × 10^10 kWh
Electricity used by an average American household = 1.04 × 10^4 kWh
Number of households served = (Total electricity generated) / (Electricity used by an average household)
= (2.496 × 10^10 kWh) / (1.04 × 10^4 kWh)
Now we need to divide the coefficients and subtract the exponents:
= 2.496 × 10^10 / 1.04 × 10^4
= (2.496 / 1.04) × (10^10 / 10^4)
= 2.4 × 10^6
Therefore, the power station can serve approximately 2.4 × 10^6 households.
To find out how many miles are there in 3.52 × 10^7 meters, we need to divide the given distance in meters by the conversion factor of meters to miles.
Number of miles = (Distance in meters) / (Conversion factor of meters to miles)
= (3.52 × 10^7 meters) / (1.6 × 10^3 meters)
Now we need to divide the coefficients and subtract the exponents:
= 3.52 / 1.6 × 10^7 / 10^3
= 2.2 × 10^4
Therefore, there are approximately 2.2 × 10^4 miles in 3.52 × 10^7 meters.
There are about 1.6×10^3 meters in a mile. About how many miles are there in 3.52×10^7 meters? Write your answer in scientific notation, expressed to the exact decimal place.(1 point)
An online data storage facility has 1.326×10^13 bytes of storage available. It has 2.6×10^4 customers. How many bytes of storage can each customer use? Write your answer in scientific notation, expressed to the exact decimal place.(1 point)
To find out how many neon tetras the aquarium can house, we need to divide the total gallons of water in the aquarium by the amount of water each neon tetra needs.
Total gallons of water in the aquarium = 1 × 10^5 gallons
Water needed per neon tetra = 1.25 gallons
Number of tetras that can be housed = (Total gallons of water) / (Water needed per neon tetra)
= (1 × 10^5 gallons) / (1.25 gallons)
Now we need to divide the coefficients and subtract the exponents:
= 1 / 1.25 × 10^5 / 1
= 0.8 × 10^5
Therefore, the aquarium can house approximately 0.8 × 10^5, or 8 × 10^4, neon tetras.
A feather weighs 0.0082 g. How many feathers would you need to make a weight of 4.1×10^3 g? Write the answer in scientific notation.(1 point)
To find out how many feathers would be needed to make a weight of 4.1 × 10^3 g, we need to divide the total weight by the weight of each feather.
Weight of each feather = 0.0082 g
Total weight desired = 4.1 × 10^3 g
Number of feathers needed = (Total weight desired) / (Weight of each feather)
= (4.1 × 10^3 g) / (0.0082 g)
Now we need to divide the coefficients and subtract the exponents:
= 4.1 / 0.0082 × 10^3 / 1
= 500 × 10^3
Therefore, you would need approximately 500 × 10^3, or 5 × 10^5, feathers to make a weight of 4.1 × 10^3 g.
A rectangular park has an area of 1.36×10^8 ft2 . The length of the park is 1.6×10^4 ft. Divide the area by the length to find the width of the park.(1 point)
Responses
To find the width of the park, we need to divide the area of the park by the length of the park.
Area of the park = 1.36 × 10^8 ft^2
Length of the park = 1.6 × 10^4 ft
Width of the park = (Area of the park) / (Length of the park)
= (1.36 × 10^8 ft^2) / (1.6 × 10^4 ft)
Now we need to divide the coefficients and subtract the exponents:
= 1.36 / 1.6 × 10^8 / 10^4
= 0.85 × 10^4 / 1
Therefore, the width of the park is 0.85 × 10^4 ft, or 8.5 × 10^3 ft.
divide 3.3×10^4 by 5.5×10^7
.(1 point)