2Hg + O2 -----> 2Hgo
if the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the mercury and oxygen on the reactants side of the equation
wrong
I apologize for the mistake. Let me recalculate.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to find the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.
thats incorrect
I apologize once again for the mistake. Let me recalculate.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to consider the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.
In the balanced chemical equation 2Hg + O2 → 2HgO, it is indicated that two atoms of mercury (Hg) react with one molecule of oxygen (O2) to form two molecules of mercuric oxide (HgO).
To find the total mass of mercury and oxygen on the reactants' side, we need to calculate the molar mass of mercury (Hg) and oxygen (O2), and then multiply them by their respective stoichiometric coefficients.
The molar mass of mercury (Hg) is 200.59 g/mol (approximately) and the oxygen (O2) is 32 g/mol (16 g/mol for each oxygen atom).
Now, let's calculate the mass of mercury:
2 mol of Hg x 200.59 g/mol = 401.18 g
And for oxygen:
1 mol of O2 x 32 g/mol = 32 g
Adding the mass of mercury and oxygen:
401.18 g + 32 g = 433.18 g
Therefore, the total mass of mercury and oxygen on the reactants' side is approximately 433.18 grams.
To find the total mass of the reactants (mercury and oxygen), we need to compare the ratio between the product (mercuric oxide, HgO) and the reactants in the balanced chemical equation.
From the balanced equation:
2Hg + O2 → 2HgO
We can see that two moles of mercury (2Hg) react with one mole of oxygen (O2) to produce two moles of mercuric oxide (2HgO).
To calculate the total mass of the reactants, you need to know the molar masses of mercury (Hg) and oxygen (O).
- The molar mass of mercury (Hg) is approximately 200.59 g/mol.
- The molar mass of oxygen (O) is approximately 16.00 g/mol.
Now, let's proceed with the calculation:
1) Determine the molar mass of mercuric oxide (HgO):
The molar mass of HgO is calculated by adding the molar masses of mercury (Hg) and oxygen (O):
Molar mass of HgO = (1 × molar mass of Hg) + (1 × molar mass of O)
Molar mass of HgO = (1 × 200.59 g/mol) + (16.00 g/mol)
Molar mass of HgO = 216.59 g/mol
2) Calculate the total moles of mercuric oxide (HgO) in the reaction:
The total moles of HgO can be determined by dividing the given mass of HgO by its molar mass:
Total moles of HgO = Total mass of HgO / Molar mass of HgO
Total moles of HgO = 433.2 g / 216.59 g/mol
Total moles of HgO = 2 moles
3) Determine the moles of mercury (Hg) and oxygen (O) in the reaction:
Since the ratio of Hg to HgO is 2:2 and the ratio of O to HgO is 1:2, we can conclude that the moles of Hg and O are equal to the moles of HgO:
Moles of Hg = Total moles of HgO = 2 moles
Moles of O = Total moles of HgO = 2 moles
4) Calculate the total mass of the reactants:
The total mass of the reactants can now be determined by multiplying the moles of each element by their respective molar masses:
Total mass of Hg = Moles of Hg × Molar mass of Hg
Total mass of Hg = 2 moles × 200.59 g/mol
Total mass of Hg = 401.18 g
Total mass of O = Moles of O × Molar mass of O
Total mass of O = 2 moles × 16.00 g/mol
Total mass of O = 32.00 g
Therefore, the total mass of the mercury and oxygen on the reactants' side of the equation is:
Total mass of Hg + O = Total mass of Hg + Total mass of O
Total mass of Hg + O = 401.18 g + 32.00 g
Total mass of Hg + O = 433.18 g
In the balanced chemical equation:
2Hg + O2 -> 2HgO
The coefficient of Hg is 2, meaning there are 2 moles of Hg involved in the reaction. The atomic mass of Hg is 200.59 g/mol. Therefore, the total mass of Hg on the reactants side is:
2 moles Hg * 200.59 g/mol = 401.18 grams
The coefficient of O2 is 1, meaning there is 1 mole of O2 involved in the reaction. The molar mass of O2 is 32 g/mol. Therefore, the total mass of O2 on the reactants side is:
1 mole O2 * 32 g/mol = 32 grams
So, the total mass of the mercury and oxygen on the reactants side of the equation is the sum of the mass of Hg and O2:
401.18 grams + 32 grams = 433.18 grams
Thus, the total mass of the mercury and oxygen on the reactants side of the equation is 433.18 grams.