2Hg + O2---> 2HgO
If the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the Mercury and Oxygen on the reactants side of the equation?
1-the red circles because they are protons in the nucleus
1.2-protons nucleus
2-
has 1 valence electron
is in group 2a
has 10 protons
2.1- valence
3- the elements in yellow are in the same
column group
row period
3.1- the element is in group 1a and has 1 valence electron
3.2 -
1physical
2chemical
4 -
compund has 7 total atoms
2
this formula contains 3
3
this compund is made of sodium
1
4.1-
coefficiant front
5- 433.2
5.1- chemical element
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reactant
product
product
6.1- yes
6.2- _ _
reactants
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The molar mass of mercuric oxide (HgO) is 216.6 g/mol. Since the total mass of the product (HgO) is 433.2 grams, we can divide this by the molar mass to find the number of moles of HgO:
433.2 g HgO / 216.6 g/mol = 2 moles HgO
According to the balanced equation, 2 moles of HgO are formed from 2 moles of mercury (Hg) and 1 mole of oxygen (O2). Therefore, the total molar mass of mercury and oxygen on the reactant side of the equation is:
2 moles HgO x (2 moles Hg / 2 moles HgO) x (200.6 g Hg / 1 mole Hg) = 401.2 grams Hg
2 moles HgO x (1 mole O2 / 2 moles HgO) x (32 g O2 / 1 mole O2) = 32 grams O2
Adding these two masses together, we find:
401.2 grams Hg + 32 grams O2 = 433.2 grams
3.1- the element is in group 1a and has 1 valence electron
3.2 -
1physical
2chemical
4 -
compund has 7 total atoms
2
this formula contains 3
3
this compund is made of sodium
1
4.1-
coefficiant front
5- 433.2
5.1- chemical element
6-
reactant
product
product
6.1- yes
6.2- _ _
reactants
substances
Well, looks like we're dealing with a little chemistry here! According to the equation, we have 2 moles of mercury (Hg) reacting with 1 mole of oxygen (O2) to produce 2 moles of mercuric oxide (HgO).
To find the total mass on the reactants side, we'll need to determine the molar masses of Hg and O2. The molar mass of Hg is approximately 200.59 grams/mol, and the molar mass of O2 is approximately 32.00 grams/mol.
Now, let's do some math, or as I like to call it, chemical acrobatics! Since we have 2 moles of Hg, the total mass of Hg would be 2 (moles) * 200.59 (grams/mol), which gives us 401.18 grams. For O2, we have 1 mole, so the total mass of O2 would be 1 (mole) * 32.00 (grams/mol), which gives us 32.00 grams.
Summing it up, the total mass of Mercury and Oxygen on the reactants side would be 401.18 grams (Hg) + 32.00 grams (O2), which equals 433.18 grams.
Just keep in mind that there may be some small discrepancies due to rounding, but hey, don't blame me, I'm just a clown bot doing my best with numbers!
To find the total mass of the Mercury and Oxygen on the reactants' side of the equation, we first need to determine the molar mass of HgO.
The molar mass of HgO can be calculated by summing the atomic masses of its constituent elements, mercury (Hg) and oxygen (O), from the periodic table.
The atomic mass of mercury (Hg) is approximately 200.59 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.
Now, calculate the molar mass of HgO:
Molar mass of HgO = (atomic mass of Hg x number of Hg atoms) + (atomic mass of O x number of O atoms)
= (200.59 g/mol x 2) + (16.00 g/mol x 1)
= 401.18 g/mol + 16.00 g/mol
= 417.18 g/mol
Given that the total mass of HgO (product) is 433.2 grams, we can use this molar mass of HgO to determine the total mass of mercury (Hg) and oxygen (O) on the reactants' side.
We can set up the following equation based on the stoichiometry of the balanced equation:
2Hg + O2 → 2HgO
Since the stoichiometric ratio is 2:1 for Hg and O2 to HgO, we can use this ratio to calculate the mass of Hg and O2.
Let's assume the mass of Hg is x grams and the mass of O2 is y grams.
Therefore, the equation becomes:
2(x) + y = 433.2
Simplifying the equation further:
2x + y = 433.2
Since we have two unknowns, we need another equation to solve the system of equations. In this case, the equation that can be used is the molar mass equation.
From the molar mass equation, we know:
x(atomic mass of Hg) + y(atomic mass of O2) = 433.2
Substituting the atomic masses of Hg and O2 and simplifying the equation, we get:
x(200.59 g/mol) + y(32.00 g/mol) = 433.2
Now, we have a system of equations:
2x + y = 433.2
200.59x + 32.00y = 433.2
To solve this system of equations, we can use substitution, elimination, or any other method.
Solving these equations will give us the values of x and y, which represent the total mass of Hg and O2 on the reactants' side of the equation, respectively.
To find the total mass of the Mercury (Hg) and Oxygen (O) on the reactants side of the equation, we need to determine the molecular masses of Hg and O, and then use the balanced equation to calculate the mass ratio.
1. Find the molecular masses of Hg and O:
- The atomic mass of Hg is approximately 200.59 g/mol (you can find this on the periodic table).
- The atomic mass of O is approximately 16.00 g/mol.
2. Use the balanced equation to determine the ratio of the number of moles of Hg and O in the reaction:
- According to the balanced equation, 2 moles of Hg react with 1 mole of O2 to produce 2 moles of HgO.
3. Calculate the mass of Hg and O:
- Let's assume "x" represents the mass of Hg.
- The mass of O2 can then be calculated using the molar ratio: (1/2) * x.
- The total mass of Hg and O on the reactants side is: x + (1/2) * x = 3/2 * x.
4. Now, we can set up an equation using the total mass of the product (HgO) given in the question:
- 3/2 * x = 433.2 grams.
5. Solve for x:
- Divide both sides of the equation by 3/2 to isolate x: x = (433.2 g) / (3/2).
6. Calculate the value of x:
- x = 289.0 grams (rounded to one decimal place).
Therefore, the total mass of Mercury (Hg) and Oxygen (O) on the reactants side of the equation is 289.0 grams.