A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days
Every 3 hours, the water tank decreases by 10 gallons. So in 24 hours, the water tank decreases by 10*8 = <<10*8=80>>80 gallons.
If after 24 hours the water tank decreases by 80 gallons, after 6 days, it decreases by 80*6 = <<80*6=480>>480 gallons. Answer: \boxed{480}.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change per day and multiply it by the number of days.
The tank decreases by 10 gallons every 3 hours. Since there are 24 hours in a day, the tank decreases by 10/3 = 3.33 gallons per hour.
Since we want to calculate the change per day, we multiply this by 24 hours, so the tank decreases by 3.33 * 24 = 79.92 gallons per day.
Therefore, after 6 days, the total change in the amount of water in the tank is 79.92 * 6 = 479.52 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change in water level for one day and then multiply it by the number of days.
Given that the water tank decreases by 10 gallons every 3 hours, we can first calculate the change in water level for one hour.
Since there are 24 hours in a day, we divide the change per 3 hours by 3 to get the change per hour:
10 gallons / 3 hours = 3.33 gallons per hour (rounded to two decimal places)
Now, we can calculate the change in water level for one day:
3.33 gallons per hour * 24 hours = 79.92 gallons per day (rounded to two decimal places)
Finally, we can calculate the total change in the amount of water in the tank after 6 days:
79.92 gallons per day * 6 days = 479.52 gallons (rounded to two decimal places)
Therefore, the total change in the amount of water in the tank after 6 days is approximately 479.52 gallons.