how much energy is required to raise temperature of 40 g of water by 20 degrees C? cw = 4.18 x 10 quipped J/ kg .C
To calculate the energy required to raise the temperature of water, we can use the formula:
Energy = mass * specific heat capacity * temperature change
Given:
mass of water (m) = 40 g = 0.04 kg
specific heat capacity of water (cw) = 4.18 x 10^3 J/(kg·°C)
temperature change (ΔT) = 20 °C
Substituting these values into the formula:
Energy = 0.04 kg * (4.18 x 10^3 J/(kg·°C)) * 20 °C
Simplifying the expression:
Energy = 0.04 kg * (4.18 x 10^3 J/(kg·°C)) * 20 °C
Energy = 0.0836 x 10^3 J
Energy = 83.6 J
Therefore, the energy required to raise the temperature of 40 g of water by 20 degrees Celsius is 83.6 Joules.
To calculate the energy required to raise the temperature of a substance, you can use the formula:
Energy = mass × specific heat capacity × temperature change
Given:
Mass of water (m) = 40 g = 0.04 kg
Specific heat capacity of water (c) = 4.18 × 10^3 J/kg·°C (since 1 kJ = 10^3 J)
Temperature change (ΔT) = 20°C
Now, let's calculate the energy required:
Energy = 0.04 kg × (4.18 × 10^3 J/kg·°C) × 20°C
Energy = 0.04 kg × (4.18 × 10^3 J/kg·°C) × 20°C
Energy = 33.44 × 10^3 J
Therefore, the energy required to raise the temperature of 40 g of water by 20 degrees Celsius is 33.44 × 10^3 J.